User:Mary Mendoza/Notebook/CHEM572 Exp. Biological Chemistry II/2013/01/23: Difference between revisions
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* It was decided to prepare a 30 mM stock solution of adenosine. The calculation below shows the amount needed to obtain 30 mM of adenosine. | * It was decided to prepare a 30 mM stock solution of adenosine. The calculation below shows the amount needed to obtain 30 mM of adenosine. | ||
.030 <math>\frac{mol}{L}</math> of adenosine × <math>\frac{267.24 g}{1 mol}</math> | .030 <math>\frac{mol}{L}</math> mol of adenosine × <math>\frac{267.24 g}{1 mol}</math> = <math>\frac{8.0172 g}{L}</math> × .010 L = 0.0802 g | ||
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Calculation of reagents for ADA kinetic assay
.030 [math]\displaystyle{ \frac{mol}{L} }[/math] mol of adenosine × [math]\displaystyle{ \frac{267.24 g}{1 mol} }[/math] = [math]\displaystyle{ \frac{8.0172 g}{L} }[/math] × .010 L = 0.0802 g
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