User:Madeleine Y. Bee/Notebook/CHEM-581 Experimental Chemistry/2014/09/05: Difference between revisions

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**A<sub>615</sub>=ε<sub>615</sub>bc → c=A<sub>615</sub>/ε<sub>615</sub>b:<br.>
**A<sub>615</sub>=ε<sub>615</sub>bc → c=A<sub>615</sub>/ε<sub>615</sub>b:<br.>
*#PVA film in 200 ppm
*#PVA film in 200 ppm
*#*c<sub>soln</sub>=(0.092)/(0.1293)(1)= x100=
*#*c<sub>soln</sub>=(0.092)/(0.1293)(1)= 0.716M=  ppm ×100=
*#PVA film in 80 ppm
*#PVA film in 80 ppm
*#*c<sub>soln</sub>=(0.094)/(0.1293)(1)= x50=
*#*c<sub>soln</sub>=(0.094)/(0.1293)(1)= 0.727M=  ppm ×50=
*#PVA film in 8 ppm
*#PVA film in 8 ppm
*#*c<sub>soln</sub>=(0.064)/(0.1293)(1)=
*#*c<sub>soln</sub>=(0.064)/(0.1293)(1)= 0.495M=  ppm
*#PVA film in 2 ppm
*#PVA film in 2 ppm
*#*c<sub>soln</sub>=(0.009)/(0.1293)(1)=
*#*c<sub>soln</sub>=(0.009)/(0.1293)(1)= 0.070M=  ppm
*#PVA Clay film in 200 ppm
*#PVA Clay film in 200 ppm
*#*c<sub>soln</sub>=(0.019)/(0.1293)(1)= x100=
*#*c<sub>soln</sub>=(0.019)/(0.1293)(1)= 0.147M=  ppm ×100=
*#PVA Clay film in 80 ppm
*#PVA Clay film in 80 ppm
*#*c<sub>soln</sub>=(0.010)/(0.1293)(1)= x50=
*#*c<sub>soln</sub>=(0.010)/(0.1293)(1)= 0.077M= ppm ×50=
*#PVA Clay film in 8 ppm
*#PVA Clay film in 8 ppm
*#*c<sub>soln</sub>=(0.041)/(0.1293)(1)=
*#*c<sub>soln</sub>=(0.041)/(0.1293)(1)= 0.317M=  ppm
*#PVA Clay film in 2 ppm
*#PVA Clay film in 2 ppm
*#*c<sub>soln</sub>=(0.004)/(0.1293)(1)=
*#*c<sub>soln</sub>=(0.004)/(0.1293)(1)= 0.031M=  ppm


**ε<sub>425</sub>=0.0266<br.>
**ε<sub>425</sub>=0.0266<br.>
**A<sub>425</sub>=ε<sub>425</sub>bc → c=A<sub>425</sub>/ε<sub>425</sub>b:<br.>
**A<sub>425</sub>=ε<sub>425</sub>bc → c=A<sub>425</sub>/ε<sub>425</sub>b:<br.>
*#PVA film in 200 ppm
*#PVA film in 200 ppm
*#*c<sub>soln</sub>=(0.)/(0.1293)(1)= x100=
*#*c<sub>soln</sub>=(0.019)/(0.1293)(1)= 0.147M=  ppm ×100=
*#PVA film in 80 ppm
*#PVA film in 80 ppm
*#*c<sub>soln</sub>=(0.)/(0.1293)(1)= x50=
*#*c<sub>soln</sub>=(0.020)/(0.1293)(1)= 0.155M=  ppm ×50=
*#PVA film in 8 ppm
*#PVA film in 8 ppm
*#*c<sub>soln</sub>=(0.)/(0.1293)(1)=
*#*c<sub>soln</sub>=(0.017)/(0.1293)(1)= 0.131M=  ppm
*#PVA film in 2 ppm
*#PVA film in 2 ppm
*#*c<sub>soln</sub>=(0.)/(0.1293)(1)=
*#*c<sub>soln</sub>=(0.003)/(0.1293)(1)= 0.023M=  ppm
*#PVA Clay film in 200 ppm
*#PVA Clay film in 200 ppm
*#*c<sub>soln</sub>=(0.)/(0.1293)(1)= x100=
*#*c<sub>soln</sub>=(0.005)/(0.1293)(1)= 0.039M=  ppm ×100=
*#PVA Clay film in 80 ppm
*#PVA Clay film in 80 ppm
*#*c<sub>soln</sub>=(0.)/(0.1293)(1)= x50=
*#*c<sub>soln</sub>=(0.003)/(0.1293)(1)= 0.023M=  ppm ×50=
*#PVA Clay film in 8 ppm
*#PVA Clay film in 8 ppm
*#*c<sub>soln</sub>=(0.)/(0.1293)(1)=
*#*c<sub>soln</sub>=(0.006)/(0.1293)(1)= 0.046M=  ppm
*#PVA Clay film in 2 ppm
*#PVA Clay film in 2 ppm
*#*c<sub>soln</sub>=(0.)/(0.1293)(1)=
*#*c<sub>soln</sub>=(0.003)/(0.1293)(1)= 0.023M=  ppm


*Determine the equilibrium of free Malachite green vs bound malachite green with I.C.E. table
*Determine the equilibrium of free Malachite green vs bound malachite green with I.C.E. table

Revision as of 12:25, 8 September 2014

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September 5, 2014

Procedures

Completing Film Synthesis

Continued from Friday, 8/29/2014<br.> Procedure detailed by Dr Hartings

  • Stir in Sodium Sulfate, 1% HCl, and Sodium Bicarbonate solutions

Beginning New Film Synthesis

Procedure detailed by Dr Hartings

  • Polymer-10% Clay Film
    • 1.0004 g PVA and 0/1077 g sodium montmorillonite (~1g PVA and ~.1g NaM)
  • Polymer Film
    • 1.0050 g PVA (~1g)

UV-vis Measurements

  • Take UV Vis spectra for Malachite green at the following concentrations: 0ppm, 0.20ppm, 0.50ppm, 1.1ppm, 1.4ppm, 1.7ppm, and 2.0ppm
  • Construct calibration curve for each of the two absorbance maximums

<br.>

Equilibrium Measurements

  • Dilute 200 ppm solutions 100x and 80 ppm solutions 50x to 10 mL & transfer to glass test tube (3 mL needed for absorbance measurements)

  • Determine the amount of Malachite green absorbed into a film
    • ε615=0.1293<br.>
    • A615615bc → c=A615615b:<br.>
    1. PVA film in 200 ppm
      • csoln=(0.092)/(0.1293)(1)= 0.716M= ppm ×100=
    2. PVA film in 80 ppm
      • csoln=(0.094)/(0.1293)(1)= 0.727M= ppm ×50=
    3. PVA film in 8 ppm
      • csoln=(0.064)/(0.1293)(1)= 0.495M= ppm
    4. PVA film in 2 ppm
      • csoln=(0.009)/(0.1293)(1)= 0.070M= ppm
    5. PVA Clay film in 200 ppm
      • csoln=(0.019)/(0.1293)(1)= 0.147M= ppm ×100=
    6. PVA Clay film in 80 ppm
      • csoln=(0.010)/(0.1293)(1)= 0.077M= ppm ×50=
    7. PVA Clay film in 8 ppm
      • csoln=(0.041)/(0.1293)(1)= 0.317M= ppm
    8. PVA Clay film in 2 ppm
      • csoln=(0.004)/(0.1293)(1)= 0.031M= ppm
    • ε425=0.0266<br.>
    • A425425bc → c=A425425b:<br.>
    1. PVA film in 200 ppm
      • csoln=(0.019)/(0.1293)(1)= 0.147M= ppm ×100=
    2. PVA film in 80 ppm
      • csoln=(0.020)/(0.1293)(1)= 0.155M= ppm ×50=
    3. PVA film in 8 ppm
      • csoln=(0.017)/(0.1293)(1)= 0.131M= ppm
    4. PVA film in 2 ppm
      • csoln=(0.003)/(0.1293)(1)= 0.023M= ppm
    5. PVA Clay film in 200 ppm
      • csoln=(0.005)/(0.1293)(1)= 0.039M= ppm ×100=
    6. PVA Clay film in 80 ppm
      • csoln=(0.003)/(0.1293)(1)= 0.023M= ppm ×50=
    7. PVA Clay film in 8 ppm
      • csoln=(0.006)/(0.1293)(1)= 0.046M= ppm
    8. PVA Clay film in 2 ppm
      • csoln=(0.003)/(0.1293)(1)= 0.023M= ppm
  • Determine the equilibrium of free Malachite green vs bound malachite green with I.C.E. table
  • Determine the mass of malachite green absorbed per mass of film