User:Klare Lazor/Notebook/Chem-496-001/2013/04/12

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Current revision (19:55, 17 April 2013) (view source)
(Description)
 
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==Description==
==Description==
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'''NOTE: Mass of whole hydrogel: 12.1419 grams, piece of hydrogel 0.8 grams, so instead of 0.193 grams to occupy all the butane-1-ol sites(0.000017mols) 0.014 grams of dye  is needed.'''
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'''NOTE: Mass of whole hydrogel: 12.1419 grams, piece of hydrogel 0.8 grams, so instead of 0.193 grams to occupy all the butayne-1-ol sites(0.000017mols) an amount of 0.014 grams of dye  is needed.'''
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*the stock solution of dye is 5mg/ml=5g/L therefore the amount of grams of dye in vial, as well as assuming 1:1 reaction between butane-1-ol and dye then successful reaction will have a percent reacted of
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*the stock solution of dye is 5mg/ml=5g/L therefore the amount of grams of dye in vial, as well as assuming 1:1 reaction between butane-1-ol and dye then a successful reaction will have a percent reacted ~ equal to the percentages below. Percentages below are equal to the amount of dye in mols added to the film/the amount of mols that should react with the butane-1-ol times 100.
**'''1µL of Dye'''= 0.000005g= 8.9E-9 mol/0.000017mols= 0.0523%
**'''1µL of Dye'''= 0.000005g= 8.9E-9 mol/0.000017mols= 0.0523%
**'''10µL of Dye'''= 0.00005g=8.9E-8 mols/0.000017= 0.523%
**'''10µL of Dye'''= 0.00005g=8.9E-8 mols/0.000017= 0.523%

Current revision

Biomaterials Design Lab Main project page
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Objective

  • Read plates
  • took florescence of the differ concentrations used with hydrogel pieces and determined the concentrations/mols of dye attached

Description

NOTE: Mass of whole hydrogel: 12.1419 grams, piece of hydrogel 0.8 grams, so instead of 0.193 grams to occupy all the butayne-1-ol sites(0.000017mols) an amount of 0.014 grams of dye is needed.

  • the stock solution of dye is 5mg/ml=5g/L therefore the amount of grams of dye in vial, as well as assuming 1:1 reaction between butane-1-ol and dye then a successful reaction will have a percent reacted ~ equal to the percentages below. Percentages below are equal to the amount of dye in mols added to the film/the amount of mols that should react with the butane-1-ol times 100.
    • 1µL of Dye= 0.000005g= 8.9E-9 mol/0.000017mols= 0.0523%
    • 10µL of Dye= 0.00005g=8.9E-8 mols/0.000017= 0.523%
    • 100µL of Dye= 0.0005g=8.9E-7mols/.000017= 5.23%
    • 200µl of dye= 0.001g= 1.8E-6mols/.000017= 10.5%
    • 500µl of dye= .0025g= 4.4E-6 mols/.000017= 25.8%


1µL of Dye number of mols of dye

  • starting solution: 8.9E-9 mols
  • after soaking for 24hours with gel: 1.34E-9 mols
  • leached in water solution after 24 hours: 4.3919E-9 mols
    • 8.9E-9mols- 1.34E-9mols=7.56E-9mols of dye soaked up by gel in 24 hours
    • 7.56E-9mols - 4.3919E-9mols= 3.17E-9 mols of dye in hydrogel actual
    • mols butyne-1-ol sites in small piece of hydrogel (assuming 1:1 reaction): 0.000017
  • Percent of dye reacted with butyne-1-ol=0.0186%


10µL of Dye number of mols of dye

  • starting solution: 8.9E-8
  • after soaking for 24hours with gel: 8.8E-9 mols
  • leached in water solution after 24 hours: 3.86E-9
    • 8.9E-8 mols- 8.8E-9mols= 8.03E-8 mols of dye soaked up by gel in 24 hours
    • 8.03E-8mols - 3.86E-9mols= 7.64E-8 mols of dye in hydrogel actual
    • mols of butyne-1-ol sites in small piece of hydrogel: 0.000017
  • Percent of dye reacted with butyne-1-ol= 0.45% error possibility or slice of film had more sites


100µL of Dye number of mols of dye

  • starting solution: 8.9E-7mols
  • after soaking for 24hours with gel: 1.608E-7mols
  • leached in water solution after 24 hours: 3.856E-9 mols
    • 8.9E-7 mols- 1.608E-7mols= 7.3E-7 mols of dye soaked up by gel in 24 hours
    • 7.3E-7mols - 3.86E-7mols= 7.26E-7 mols of dye in hydrogel actual
    • mols of butyne-1-ol sites in small piece of hydrogel: 0.000017
  • Percent of dye reacted with butyne-1-ol= 4.27% Error possibility or slice of film had more sites


200µl of dye number of mols of dye

  • starting solution: 1.8E-6mols
  • after soaking for 24hours with gel: 4.6E-7mols
  • leached in water solution after 24 hours: 1.6E-7 mols
    • 1.8E-6 mols- 4.6E-7mols= 1.34E-6 mols of dye soaked up by gel in 24 hours
    • 1.34E-6mols - 1.6E-7mols= 1.18E-6 mols of dye in hydrogel actual
    • mols of butyne-1-ol sites in small piece of hydrogel: 0.000017
  • Percent of dye reacted with butyne-1-ol= 6.94%


500µl of dye number of mols of dye

  • starting solution: 4.4E-6mols
  • after soaking for 24hours with gel: 8.8E-7 mols
  • leached in water solution after 24 hours: 8.4E-7 mols
    • 4.4E-6 mols- 8.8E-7mols= 3.5E-6 mols of dye soaked up by gel in 24 hours
    • 3.5E-6mols - 8.4E-7mols= 2.67E-6 mols of dye in hydrogel actual
    • mols of butyne-1-ol sites in small piece of hydrogel: 0.000017
  • Percent of dye reacted with butyne-1-ol= 15.71%

Data

  • Add data and results here...

Notes

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