User:Klare Lazor/Notebook/Chem-496-001/2013/04/12

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==Description==
==Description==
 +
'''NOTE: Mass of whole hydrogel: 12.1419 grams, piece of hydrogel 0.8 grams, so instead of 0.193 grams to occupy all the butane-1-ol sites 0.014 grams (2.5E-5mols) is needed.'''
 +
*the stock solution of dye is 5mg/ml=5g/L therefore the amount of grams of dye in vial, as well as assuming 1:1 reaction between butane-1-ol and dye then successful reaction will have a percent reacted of
 +
**'''1µL of Dye'''= 0.000005g= 8.9E-9 mol= 0.0356&
 +
**'''10µL of Dye'''= 0.00005g=8.9E-8 mols= 0.356%
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**'''100µL of Dye'''= 0.0005g=8.9E-7mols= 3.56%
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**'''200µl of dye'''= 0.001g= 1.8E-6mols= 7.2%
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**'''500µl of dye'''= .0025g= 4.4E-6 mols= 17.747%
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'''1µL of Dye'''
'''1µL of Dye'''
number of mols of dye
number of mols of dye
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** 8.03E-8mols - 3.86E-9mols= '''7.64E-8 mols of dye in hydrogel actual'''
** 8.03E-8mols - 3.86E-9mols= '''7.64E-8 mols of dye in hydrogel actual'''
** mols of butyne-1-ol sites in small piece of hydrogel: 0.000017  
** mols of butyne-1-ol sites in small piece of hydrogel: 0.000017  
-
*Percent of dye reacted with butyne-1-ol= 0.45%
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*Percent of dye reacted with butyne-1-ol= 0.45% '''error possibility or slice of film had more sites'''
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** 7.3E-7mols - 3.86E-7mols= '''7.26E-7 mols of dye in hydrogel actual'''
** 7.3E-7mols - 3.86E-7mols= '''7.26E-7 mols of dye in hydrogel actual'''
**mols of butyne-1-ol sites in small piece of hydrogel: 0.000017  
**mols of butyne-1-ol sites in small piece of hydrogel: 0.000017  
-
*Percent of dye reacted with butyne-1-ol= 4.27%
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*Percent of dye reacted with butyne-1-ol= 4.27% '''Error possibility or slice of film had more sites'''

Revision as of 21:28, 15 April 2013

Biomaterials Design Lab Main project page
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Objective

  • Read plates
  • took florescence of the differ concentrations used with hydrogel pieces and determined the concentrations/mols of dye attached

Description

NOTE: Mass of whole hydrogel: 12.1419 grams, piece of hydrogel 0.8 grams, so instead of 0.193 grams to occupy all the butane-1-ol sites 0.014 grams (2.5E-5mols) is needed.

  • the stock solution of dye is 5mg/ml=5g/L therefore the amount of grams of dye in vial, as well as assuming 1:1 reaction between butane-1-ol and dye then successful reaction will have a percent reacted of
    • 1µL of Dye= 0.000005g= 8.9E-9 mol= 0.0356&
    • 10µL of Dye= 0.00005g=8.9E-8 mols= 0.356%
    • 100µL of Dye= 0.0005g=8.9E-7mols= 3.56%
    • 200µl of dye= 0.001g= 1.8E-6mols= 7.2%
    • 500µl of dye= .0025g= 4.4E-6 mols= 17.747%


1µL of Dye number of mols of dye

  • starting solution: 8.9E-9 mols
  • after soaking for 24hours with gel: 1.34E-9 mols
  • leached in water solution after 24 hours: 4.3919E-9 mols
    • 8.9E-9mols- 1.34E-9mols=7.56E-9mols of dye soaked up by gel in 24 hours
    • 7.56E-9mols - 4.3919E-9mols= 3.17E-9 mols of dye in hydrogel actual
    • mols butyne-1-ol sites in small piece of hydrogel (assuming 1:1 reaction): 0.000017
  • Percent of dye reacted with butyne-1-ol=0.0186%


10µL of Dye number of mols of dye

  • starting solution: 8.9E-8
  • after soaking for 24hours with gel: 8.8E-9 mols
  • leached in water solution after 24 hours: 3.86E-9
    • 8.9E-8 mols- 8.8E-9mols= 8.03E-8 mols of dye soaked up by gel in 24 hours
    • 8.03E-8mols - 3.86E-9mols= 7.64E-8 mols of dye in hydrogel actual
    • mols of butyne-1-ol sites in small piece of hydrogel: 0.000017
  • Percent of dye reacted with butyne-1-ol= 0.45% error possibility or slice of film had more sites


100µL of Dye number of mols of dye

  • starting solution: 8.9E-7mols
  • after soaking for 24hours with gel: 1.608E-7mols
  • leached in water solution after 24 hours: 3.856E-9 mols
    • 8.9E-7 mols- 1.608E-7mols= 7.3E-7 mols of dye soaked up by gel in 24 hours
    • 7.3E-7mols - 3.86E-7mols= 7.26E-7 mols of dye in hydrogel actual
    • mols of butyne-1-ol sites in small piece of hydrogel: 0.000017
  • Percent of dye reacted with butyne-1-ol= 4.27% Error possibility or slice of film had more sites


200µl of dye number of mols of dye

  • starting solution: 1.8E-6mols
  • after soaking for 24hours with gel: 4.6E-7mols
  • leached in water solution after 24 hours: 1.6E-7 mols
    • 1.8E-6 mols- 4.6E-7mols= 1.34E-6 mols of dye soaked up by gel in 24 hours
    • 1.34E-6mols - 1.6E-7mols= 1.18E-6 mols of dye in hydrogel actual
    • mols of butyne-1-ol sites in small piece of hydrogel: 0.000017
  • Percent of dye reacted with butyne-1-ol= 6.94%


500µl of dye number of mols of dye

  • starting solution: 4.4E-6mols
  • after soaking for 24hours with gel: 8.8E-7 mols
  • leached in water solution after 24 hours: 8.4E-7 mols
    • 4.4E-6 mols- 8.8E-7mols= 3.5E-6 mols of dye soaked up by gel in 24 hours
    • 3.5E-6mols - 8.4E-7mols= 2.67E-6 mols of dye in hydrogel actual
    • mols of butyne-1-ol sites in small piece of hydrogel: 0.000017
  • Percent of dye reacted with butyne-1-ol= 15.71%

Data

  • Add data and results here...

Notes

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