User:Klare Lazor/Notebook/Chem-496-001/2013/04/12: Difference between revisions

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==Description==
==Description==
'''NOTE: Mass of whole hydrogel: 12.1419 grams, piece of hydrogel 0.8 grams, so instead of 0.193 grams to occupy all the butane-1-ol sites 0.014 grams (2.5E-5mols) is needed.'''
*the stock solution of dye is 5mg/ml=5g/L therefore the amount of grams of dye in vial, as well as assuming 1:1 reaction between butane-1-ol and dye then successful reaction will have a percent reacted of
**'''1µL of Dye'''= 0.000005g= 8.9E-9 mol= 0.0356&
**'''10µL of Dye'''= 0.00005g=8.9E-8 mols= 0.356%
**'''100µL of Dye'''= 0.0005g=8.9E-7mols= 3.56%
**'''200µl of dye'''= 0.001g= 1.8E-6mols= 7.2%
**'''500µl of dye'''= .0025g= 4.4E-6 mols= 17.747%
'''1µL of Dye'''
'''1µL of Dye'''
number of mols of dye
number of mols of dye
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** 8.03E-8mols - 3.86E-9mols= '''7.64E-8 mols of dye in hydrogel actual'''
** 8.03E-8mols - 3.86E-9mols= '''7.64E-8 mols of dye in hydrogel actual'''
** mols of butyne-1-ol sites in small piece of hydrogel: 0.000017  
** mols of butyne-1-ol sites in small piece of hydrogel: 0.000017  
*Percent of dye reacted with butyne-1-ol= 0.45%
*Percent of dye reacted with butyne-1-ol= 0.45% '''error possibility or slice of film had more sites'''




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** 7.3E-7mols - 3.86E-7mols= '''7.26E-7 mols of dye in hydrogel actual'''
** 7.3E-7mols - 3.86E-7mols= '''7.26E-7 mols of dye in hydrogel actual'''
**mols of butyne-1-ol sites in small piece of hydrogel: 0.000017  
**mols of butyne-1-ol sites in small piece of hydrogel: 0.000017  
*Percent of dye reacted with butyne-1-ol= 4.27%
*Percent of dye reacted with butyne-1-ol= 4.27% '''Error possibility or slice of film had more sites'''




Revision as of 18:28, 15 April 2013

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Objective

  • Read plates
  • took florescence of the differ concentrations used with hydrogel pieces and determined the concentrations/mols of dye attached

Description

NOTE: Mass of whole hydrogel: 12.1419 grams, piece of hydrogel 0.8 grams, so instead of 0.193 grams to occupy all the butane-1-ol sites 0.014 grams (2.5E-5mols) is needed.

  • the stock solution of dye is 5mg/ml=5g/L therefore the amount of grams of dye in vial, as well as assuming 1:1 reaction between butane-1-ol and dye then successful reaction will have a percent reacted of
    • 1µL of Dye= 0.000005g= 8.9E-9 mol= 0.0356&
    • 10µL of Dye= 0.00005g=8.9E-8 mols= 0.356%
    • 100µL of Dye= 0.0005g=8.9E-7mols= 3.56%
    • 200µl of dye= 0.001g= 1.8E-6mols= 7.2%
    • 500µl of dye= .0025g= 4.4E-6 mols= 17.747%


1µL of Dye number of mols of dye

  • starting solution: 8.9E-9 mols
  • after soaking for 24hours with gel: 1.34E-9 mols
  • leached in water solution after 24 hours: 4.3919E-9 mols
    • 8.9E-9mols- 1.34E-9mols=7.56E-9mols of dye soaked up by gel in 24 hours
    • 7.56E-9mols - 4.3919E-9mols= 3.17E-9 mols of dye in hydrogel actual
    • mols butyne-1-ol sites in small piece of hydrogel (assuming 1:1 reaction): 0.000017
  • Percent of dye reacted with butyne-1-ol=0.0186%


10µL of Dye number of mols of dye

  • starting solution: 8.9E-8
  • after soaking for 24hours with gel: 8.8E-9 mols
  • leached in water solution after 24 hours: 3.86E-9
    • 8.9E-8 mols- 8.8E-9mols= 8.03E-8 mols of dye soaked up by gel in 24 hours
    • 8.03E-8mols - 3.86E-9mols= 7.64E-8 mols of dye in hydrogel actual
    • mols of butyne-1-ol sites in small piece of hydrogel: 0.000017
  • Percent of dye reacted with butyne-1-ol= 0.45% error possibility or slice of film had more sites


100µL of Dye number of mols of dye

  • starting solution: 8.9E-7mols
  • after soaking for 24hours with gel: 1.608E-7mols
  • leached in water solution after 24 hours: 3.856E-9 mols
    • 8.9E-7 mols- 1.608E-7mols= 7.3E-7 mols of dye soaked up by gel in 24 hours
    • 7.3E-7mols - 3.86E-7mols= 7.26E-7 mols of dye in hydrogel actual
    • mols of butyne-1-ol sites in small piece of hydrogel: 0.000017
  • Percent of dye reacted with butyne-1-ol= 4.27% Error possibility or slice of film had more sites


200µl of dye number of mols of dye

  • starting solution: 1.8E-6mols
  • after soaking for 24hours with gel: 4.6E-7mols
  • leached in water solution after 24 hours: 1.6E-7 mols
    • 1.8E-6 mols- 4.6E-7mols= 1.34E-6 mols of dye soaked up by gel in 24 hours
    • 1.34E-6mols - 1.6E-7mols= 1.18E-6 mols of dye in hydrogel actual
    • mols of butyne-1-ol sites in small piece of hydrogel: 0.000017
  • Percent of dye reacted with butyne-1-ol= 6.94%


500µl of dye number of mols of dye

  • starting solution: 4.4E-6mols
  • after soaking for 24hours with gel: 8.8E-7 mols
  • leached in water solution after 24 hours: 8.4E-7 mols
    • 4.4E-6 mols- 8.8E-7mols= 3.5E-6 mols of dye soaked up by gel in 24 hours
    • 3.5E-6mols - 8.4E-7mols= 2.67E-6 mols of dye in hydrogel actual
    • mols of butyne-1-ol sites in small piece of hydrogel: 0.000017
  • Percent of dye reacted with butyne-1-ol= 15.71%

Data

  • Add data and results here...

Notes

This area is for any observations or conclusions that you would like to note.


Use categories like tags. Change the "Course" category to the one corresponding to your course. The "Miscellaneous" tag can be used for particular experiments, as instructed by your professor. Please be sure to change or delete this tag as required so that the categories remain well organized.


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