User:Klare Lazor/Notebook/Chem-496-001/2013/02/11: Difference between revisions
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==Objective== | ==Objective== | ||
#crosslinking films from friday and dsc | |||
#remaking films with lower molecular weight and phenol | |||
#Discussing with fox about the failure of the synthesis of the quaternary amine | |||
==Description== | ==Description== | ||
''' | '''Film description from 7/8 Friday''' | ||
* 1% Phenol looked the best for the film with mw: 146,000-186,000 | |||
* .1% and 10% crystals were forming either phenol or pvoh or both | |||
* concluded to high of a molecular weight the crystals were most likely pvoh recrystalizing | |||
* will still attempt to crosslink and dsc on the flat areas of the films | |||
* bubbles from the high molecular weight may have also lead to less mixing and crystal formation | |||
== | '''Cross-linking PVOH (MW:146,000-186,000) Films With 0.7M HCl and neutralizing .6 Molar sodium bicarbonate''' | ||
*To high of a molecular weight will remake with with a lower molecular weight | |||
*MW: 22,000 will be used instead for this....higher molecular weight is to thick for this type of reaction with crosslinking with glutaraldehyde | |||
* 20ml of 100% H2So4 in 1 L of H20 was use for the fixant will determine amount of H+ ions in solution to determine concentartion of HCL | |||
**20ml* 1.84g/ml ÷ 98.079g/mol = 0.375moles of H2SO4 ÷ 1 Liter= 0.369 Molar H2SO4 | |||
** assume complete dissociation | |||
** 0.369mols of H2SO4/L * 2mols HCl/1mol of H2SO4 = 0.7M HCl, which is equal to 6ml of 12 M HCl in 94 ml of H2O for 1 Hour | |||
* To neutralize a NaHCO3 solution will be made, 0.7 M NaHCO3 15 minutes | |||
''' Switching to lower molecular weight: PVOH (MW: 22,000) + phenol + glutaraldehyde + 30 ml of water''' | |||
*22,000 MW PVOH → 44g/mol | |||
*1 gram PVOH/ 22,000g/mole = 4.57E-5 m oles PVOH | |||
* 22,000 g/mol PVOH / 44 g/mol = 500 OH groups per a molecule of PVOH | |||
* 4.54E-5moles PVOH * 5000 oh groups/molecule of PVOH * 6.002 E23 molecules/mol = 1.369 E 22 oh groups in 1 gram of PVOH 22000 mw | |||
* we want one OH in Phenol to react with 10%, 1%,.1% and 0.01% of oh groups in PVOH | |||
* used the 10% stock left over from last time and reduce by a factor of ten for each percentage | |||
** 1%= 1ml of stock | |||
**.1%=0.1ml of stock | |||
**.01%= 0.01 ml of stock | |||
** 10%= whatever ml left over will end up close to 10% will calculate after measuring how much stock is left over |
Revision as of 12:19, 11 February 2013
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Objective
DescriptionFilm description from 7/8 Friday
Switching to lower molecular weight: PVOH (MW: 22,000) + phenol + glutaraldehyde + 30 ml of water
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