User:Klare Lazor/Notebook/Chem-496-001/2012/09/12: Difference between revisions

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*** stock solution of 50ml 39.97g/mol(5mols/L)= 199.985 g/L * .050 L = 9.99 g of NaOH to 50mL to make a 5 Molar stock solution
*** stock solution of 50ml 39.97g/mol(5mols/L)= 199.985 g/L * .050 L = 9.99 g of NaOH to 50mL to make a 5 Molar stock solution
*The pure iron oxide was directly prepared by precipitating iron salts under dropping NaOH, whereas for the composite sample, the clay was added to the iron salts mixture prior to the reaction with NaOH.
*The pure iron oxide was directly prepared by precipitating iron salts under dropping NaOH, whereas for the composite sample, the clay was added to the iron salts mixture prior to the reaction with NaOH.
* the reaction was then filtered
*The obtained materials were dried in an oven at 100 C for 3 h in air.
*The obtained materials were dried in an oven at 100 C for 3 h in air.


Revision as of 07:39, 12 September 2012

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Objective

1. PVOH(22000mw) + glutaraldehyde


2. 100% Exchanged Na-MT with HdPh3P+


3. 50% exchanged Na-MT with HDPh3P+


4. alpha-Fe3O4

Description

1. PVOH(22000mw) + glutaraldehyde

  • 0.5066g PVOH in 5ml of dissolved ( 1 small film)
  • heat stir plate to dissolved
  • then transfer to fume hood hot plate and add 1ml (0.8% by weight) of glutaraladehyde
  • pour into small disk and let harden over weekend

2. 100% Exchanged Na-MT with HdPh3P+ ((1-Hexadecyl)triphenylphosphonium Bromide)

  • (0.92 meqv/g)(1eqv/1000meqv)(2g clay(1mole HdPh3P+/eqv)(567.62 gsurfactant/mol)=1.06 g of surfactant
  • left for week to stir

3. 50% exchanged Na-MT with HDPh3P+

  • (0.92 meqv/g)(1eqv/1000meqv)(2g clay(1mole HdPh3P+/eqv)(567.62 gsurfactant/mol)=1.06 g of surfactant
  • divide the 100% grams of surfactant by 2 = 0.5352 grams of surfactant
  • left for week to stir

4. alpha-Fe3O4 1:1 ratio

  • 0.75 g FeSO4 ~ 0.83g
  • 1.56g FeCl3 ~1.93 g
    • in 10ml of distilled water with 2 grams~ 2.18 g of clay
    • add 20ml NaOH dropwise or slowly to precipitate out the iron oxide
      • stock solution of 50ml 39.97g/mol(5mols/L)= 199.985 g/L * .050 L = 9.99 g of NaOH to 50mL to make a 5 Molar stock solution
  • The pure iron oxide was directly prepared by precipitating iron salts under dropping NaOH, whereas for the composite sample, the clay was added to the iron salts mixture prior to the reaction with NaOH.
  • the reaction was then filtered
  • The obtained materials were dried in an oven at 100 C for 3 h in air.

Data

  • Add data and results here...

Notes

This area is for any observations or conclusions that you would like to note.


Use categories like tags. Change the "Course" category to the one corresponding to your course. The "Miscellaneous" tag can be used for particular experiments, as instructed by your professor. Please be sure to change or delete this tag as required so that the categories remain well organized.


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