User:Elizabeth Ghias/Notebook/Experimental Chemistry/2013/02/08: Difference between revisions
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|style="background-color: #EEE"|[[Image:BDLlogo_notext_lr.png|128px]]<span style="font-size:22px;"> Experimental Chemistry</span> | |style="background-color: #EEE"|[[Image:BDLlogo_notext_lr.png|128px]]<span style="font-size:22px;"> Experimental Chemistry</span> | ||
|style="background-color: #F2F2F2" align="center"| | |style="background-color: #F2F2F2" align="center"|[[File:Report.png|frameless|link={{#sub:{{FULLPAGENAME}}|0|-11}}]][[{{#sub:{{FULLPAGENAME}}|0|-11}}|Main project page]]<br />{{#if:{{#lnpreventry:{{FULLPAGENAME}}}}|[[File:Resultset_previous.png|frameless|link={{#lnpreventry:{{FULLPAGENAME}}}}]][[{{#lnpreventry:{{FULLPAGENAME}}}}{{!}}Previous entry]] }}{{#if:{{#lnnextentry:{{FULLPAGENAME}}}}|[[{{#lnnextentry:{{FULLPAGENAME}}}}{{!}}Next entry]][[File:Resultset_next.png|frameless|link={{#lnnextentry:{{FULLPAGENAME}}}}]]}} | ||
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* Need to get first part of calculation from Klare. | * Need to get first part of calculation from Klare. | ||
10% Film and Stock solution - 0.214 g phenol in 10 mL | |||
1% Film: M1V1 = M2V2 → (21.4 M)(X) = (2.14)(0.01 L) → X = 0.001 L = 1 mL phenol stock solution in 9 mL water | |||
0.1% Film: (21.4 M)(X) = (0.214 M)(0.01 L) → X = 0.0001 L = 0.1 mL phenol stock solution in 9.9 mL water | |||
0.01% Film: (21.4 M)(X) = (0.0214 M)(0.01 L) → X = 0.00001 L = 0.01 mL phenol stock solution in 9.99 mL water. | |||
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# Place on ice. | # Place on ice. | ||
# Add the product drop-wise | # Add the product drop-wise | ||
# Filter and collect precipitate. | # Filter and collect precipitate. See notes. | ||
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* Two 1% films were prepared to test the effects of preparing in an Erlenmeyer flask vs. a beaker. The film prepared in the flask did not have bubbles, so this is the method that will be used from now on. The film prepared in the beaker had bubbles and began to solidify before being poured. | * Two 1% films were prepared to test the effects of preparing in an Erlenmeyer flask vs. a beaker. The film prepared in the flask did not have bubbles, so this is the method that will be used from now on. The film prepared in the beaker had bubbles and began to solidify before being poured. | ||
* The 0.01% film was not prepared, because this concentration seems too low to be effective. | * The 0.01% film was not prepared, because this concentration seems too low to be effective. | ||
* | * The quaternary ammonium salt did not crash out of solution when it was added dropwise to ethyl acetate. The reaction mixture was then added to petroleum ether, but still did not crash out of solution. This indicates that the reaction likely did not occur. | ||
* Next time, we will try a new reaction with (S)-(-)-(3-Chloro-2-hydroxypropyl)trimethylammonium chloride. | |||
Latest revision as of 22:26, 26 September 2017
Experimental Chemistry | Main project page Previous entry Next entry |
ObjectiveTo prepare new films containing phenol, to purify the quaternary ammonium salt prepared on Monday, and to take an NMR of the purified salt. DescriptionPhenol Film Calculations
10% Film and Stock solution - 0.214 g phenol in 10 mL 1% Film: M1V1 = M2V2 → (21.4 M)(X) = (2.14)(0.01 L) → X = 0.001 L = 1 mL phenol stock solution in 9 mL water 0.1% Film: (21.4 M)(X) = (0.214 M)(0.01 L) → X = 0.0001 L = 0.1 mL phenol stock solution in 9.9 mL water 0.01% Film: (21.4 M)(X) = (0.0214 M)(0.01 L) → X = 0.00001 L = 0.01 mL phenol stock solution in 9.99 mL water.
Quaternary Ammonium Salt Purification
DataNo data was collected today. Notes
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