User:Elizabeth Ghias/Notebook/Experimental Chemistry/2012/09/27: Difference between revisions
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|style="background-color: #EEE"|[[Image:BDLlogo_notext_lr.png|128px]]<span style="font-size:22px;"> Experimental Chemistry</span> | |style="background-color: #EEE"|[[Image:BDLlogo_notext_lr.png|128px]]<span style="font-size:22px;"> Experimental Chemistry</span> | ||
|style="background-color: #F2F2F2" align="center"| | |style="background-color: #F2F2F2" align="center"|[[File:Report.png|frameless|link={{#sub:{{FULLPAGENAME}}|0|-11}}]][[{{#sub:{{FULLPAGENAME}}|0|-11}}|Main project page]]<br />{{#if:{{#lnpreventry:{{FULLPAGENAME}}}}|[[File:Resultset_previous.png|frameless|link={{#lnpreventry:{{FULLPAGENAME}}}}]][[{{#lnpreventry:{{FULLPAGENAME}}}}{{!}}Previous entry]] }}{{#if:{{#lnnextentry:{{FULLPAGENAME}}}}|[[{{#lnnextentry:{{FULLPAGENAME}}}}{{!}}Next entry]][[File:Resultset_next.png|frameless|link={{#lnnextentry:{{FULLPAGENAME}}}}]]}} | ||
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Latest revision as of 22:17, 26 September 2017
Experimental Chemistry | Main project page Previous entry Next entry |
ObjectiveTo do the calculations for the standard solutions of copper sulfate.
Description<html> <HEAD> <TITLE>Enter the Page Title Here</TITLE> </HEAD> <BODY> <TABLE width="75%" border="1" align="center" > <TR><TH>Standard #</TH><TH>CuSO4*5H2O (mL)</TH><TH>H2O(mL)3</TH><TH>m1v1=m2v2</TH><TH>Concentration (ppm)</></TR> <TR align="center"> <TD>1</TD><TD>0.25</TD><TD>9.75</TD><TD>(.013581g/ml)(.25ml)=x(10ml)</TD><TD>0.00033953 g/ml=.339525ppm</TD> </TR> <TR align="center"> <TD>2</TD><TD>0.50</TD><TD>9.50</TD><TD>(0.013581g/ml)(.5ml)=x(10ml)</TD><TD>0.000679g/ml=.679ppm</TD> </TR> <TR align="center"> <TD>3</TD><TD>1.00</TD><TD>9.00</TD><TD>(0.013581g/ml)(1ml)=x(10ml)</TD><TD>.0013581g/ml=1.358ppm</TD> </TR> <TR align="center"> <TD>4</TD><TD>2.00</TD><TD>8.00</TD><TD>(0.01358g/ml)(2ml)=x(10ml)</TD><TD>.002716g/ml=2.716ppm</TD> </TR> <TR align="center"> <TD>5</TD><TD>3.00</TD><TD>7.00</TD><TD>(0.01358g/ml)(3ml)=x(10ml)</TD><TD>.004074g/ml=4.074ppm</TD> </TR> <TR align="center"> <TD>6</TD><TD>7.00</TD><TD>3.00</TD><TD>(0.01358mg/ml)(7ml)=x(10ml)</TD><TD>.009506g/ml=9.5ppm</TD> </TR> <TR align="center"> <TD>7</TD><TD>10.00</TD><TD>0</TD><TD>(0.01358g/ml)(10ml)=x(10ml)</TD><TD>.01354g/ml=13.58ppm</TD> </TR> </TABLE> </BODY> </html>
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