User:Anh Do/Notebook/CHEM 481 Polymer/2016/10/19: Difference between revisions

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==Preparation of Stock Solution==
==Preparation of Stock Solution==
1. ZnCl<sub>2</sub> - 100 ppm
1. Zn - 100 ppm
* 0.02115 g of ZnCl<sub>2</sub> in 100 mL
* 0.02115 g of ZnCl<sub>2</sub> in 100 mL
** 100mL*1L/1000mL*100mg Zn/1L*138.315 g/mol ZnCl<sub>2</sub>/65.38 g/mol Zn = 21.15 mg ZnCl<sub>2</sub>
** 100mL*1L/1000mL*100mg Zn/1L*138.315 g/mol ZnCl<sub>2</sub>/65.38 g/mol Zn = 21.15 mg ZnCl<sub>2</sub>
** Mass meassured: 0.0212 g  
** Mass meassured: 0.0212 g  


2. CuCl<sub>2</sub> - 100 ppm
2. Cu - 100 ppm
* 0.0212 g of CuCl<sub>2</sub> in 100 mL
* 0.0212 g of CuCl<sub>2</sub> in 100 mL
** 100mL*1L/1000mL*100mg Cu/1L*134.45 g/mol CuCl<sub>2</sub>/63.54 g/mol Cu = 21.16 mg CuCl<sub>2</sub>
** 100mL*1L/1000mL*100mg Cu/1L*134.45 g/mol CuCl<sub>2</sub>/63.54 g/mol Cu = 21.16 mg CuCl<sub>2</sub>
** Mass meassured: 0.0214 g
** Mass meassured: 0.0214 g


3. PbAc<sub>2</sub> - 100 ppm
3. Pb - 100 ppm
* 0.0157 g of PbAc<sub>2</sub> in 100 mL
* 0.0157 g of PbAc<sub>2</sub> in 100 mL
**100mL*1L/1000mL*100mg Pb/1L*325.29 g/mol PbAc/207.2 g/mol Cu = 15.7 mg PbAc<sub>2</sub>
**100mL*1L/1000mL*100mg Pb/1L*325.29 g/mol PbAc/207.2 g/mol Cu = 15.7 mg PbAc<sub>2</sub>

Revision as of 06:50, 19 October 2016

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Testing Beads' filtration ability - Heavy Metals

1. Preparation of solution for 20 ppm concentration


Preparation of Stock Solution

1. Zn - 100 ppm

  • 0.02115 g of ZnCl2 in 100 mL
    • 100mL*1L/1000mL*100mg Zn/1L*138.315 g/mol ZnCl2/65.38 g/mol Zn = 21.15 mg ZnCl2
    • Mass meassured: 0.0212 g

2. Cu - 100 ppm

  • 0.0212 g of CuCl2 in 100 mL
    • 100mL*1L/1000mL*100mg Cu/1L*134.45 g/mol CuCl2/63.54 g/mol Cu = 21.16 mg CuCl2
    • Mass meassured: 0.0214 g

3. Pb - 100 ppm

  • 0.0157 g of PbAc2 in 100 mL
    • 100mL*1L/1000mL*100mg Pb/1L*325.29 g/mol PbAc/207.2 g/mol Cu = 15.7 mg PbAc2
    • Mass meassured: 0.0158 g

Column Preparation

1. Weight of beads inside 2. Procedure

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