User:Anh Do/Notebook/CHEM 481 Polymer/2016/09/21

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Beads formation with 30% clay Making the solution of 1.25 g PVOH, 17.325 mL of 3wt% clay, 15 mL 12.1M HCl, 22.675 mL of H2O Mass of PVOH: 1.2502 g Mass of clay: 1.25/7*3 = 0.5357 g Volumn of clay: 0.5357*100/3 ~ 17.321 mL ~ Measured: 17.325 mL Volumn of HCl: 15 mL Volumn of water: 55 - 17.325 - 15 = 22.675 mL Repeat following this protocol Higher stirring speed required Beads formation with 40% clay Making solution of 1.25 g PVOH, 27 mL bentonite 3wt%, 15 mL HCl, 13 mL H2O Mass of PVOH: 1.2506 g Volumn of bentonite solution: 27 mL Mass of clay needed: 1.25/6*4 = 0.8333 g Volumn of bentonite 3wt% needed: 0.8333*100/3 = 26.944 mL ~ 27 mL Volumn of HCl: 15 mL Volumn of water: 55 - 15 - 27 = 13 mL Repeat following this protocol Higher stirring speed required Putting beads in column Weighing the columns (data from Dominique's notes) Column Volumes (g) Activated Carbon 10% Empty Dry with Clamp 20.1234 20.1105 Clamp 4.13733 4.1437 Empty Dry 15.98607 15.9668 Empty Wet 16.38975 16.3416 Beads in Column with Clamp 22.3344 21.95 Column with Beads 18.19707 17.8063 Beads 1.8075 1.4647 Note It's important to keep the molar equivalence of HCl in the beads constant.