User:Anh Do/Notebook/CHEM 481 Polymer/2016/09/14: Difference between revisions
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*0.275 g Bentonite powder is equivalent to 8.89 mL of 3wt% Bentonite solution | *0.275 g Bentonite powder is equivalent to 8.89 mL of 3wt% Bentonite solution | ||
**0.275g*97mL/3g = 8.89 mL | **0.275g*97mL/3g = 8.89 mL | ||
* | * Volumn of HCl = 30 mL, this effectively diluted the whole solution. However, the amount in moles of HCl is the same, which is more important. | ||
* Place this solution on a hot plate and heat/stir until everything has dissolved. | * Place this solution on a hot plate and heat/stir until everything has dissolved. | ||
* Add 10 mL of this solution to a 50 mL solution of ethyl acetate stirring at 240 rpm in a dropwise manner using a burette. | * Add 10 mL of this solution to a 50 mL solution of ethyl acetate stirring at 240 rpm in a dropwise manner using a burette. | ||
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**PVOH + 10% Bentonite + 0.5 mL of Glutaraldehyde: 0.47705 g | **PVOH + 10% Bentonite + 0.5 mL of Glutaraldehyde: 0.47705 g | ||
**PVOH + 0.5 mL Glutaraldehyde: 0.06450 g | **PVOH + 0.5 mL Glutaraldehyde: 0.06450 g | ||
*The swelling capacity is | *The swelling capacity is | ||
** PVOH + 10% Bentonite + 0.5 Glutaraldehyde: (1.24545 - 0.47705)/(0.47705) = 1.61073 | |||
** PVOH + 0.5 mL Glutaraldehyde: (0.53 - 0.0645)/0.0645 = 7.21705 (This does not make sense!!!!!) | |||
4. 3% Bentonite Film cross-linking | 4. 3% Bentonite Film cross-linking |
Revision as of 06:17, 21 September 2016
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Beads formation using clay powder and clay solution1. Follow up on previous beads formation experiment
2. Beads formation using clay solution
3. Follow up on the film making procedure
4. 3% Bentonite Film cross-linking
Don't forget to fill in what you did last week. |