User:Andrew K Farag/Notebook/CHEM-581/2014/09/12: Difference between revisions

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|style="background-color: #EEE"|[[Image:BDLlogo_notext_lr.png|128px]]<span style="font-size:22px;"> Biomaterials Design Lab</span>
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### Determine how to make a film such that you make a 10% clay (1g of PVA, ?? of exfoliated clay solution).
### Determine how to make a film such that you make a 10% clay (1g of PVA, ?? of exfoliated clay solution).
## Prepare a crosslinked film with the exfoliated clay in a similar manner to your other films
## Prepare a crosslinked film with the exfoliated clay in a similar manner to your other films
# Powder Xray diffraction
## We will discuss X-ray diffraction
## You will dry and set up your samples for use in the xrd instrument.
## I will show everyone how to use the instrument
# Continue DSC analysis
# Continue DSC analysis
# Continue UVVis Analysis
# Continue UVVis Analysis
## We all need to have a discussion about what our possible sources of error are.
##set up new malachite green/PVA-film experiment.
## We may need to set up new malachite green/PVA-film experiment (just the PVA, not PVA clay at this point)
##my group set up the 8ppm malachite green (4mL of 200 ppm MG +96mL of water)
##two vials with no film were prepared as well to compare the glass absorbance.
[[Image:Newbatch.png]]


==Data==
<u>PVA - malachite green absorption </u>
# Mass of empty vials
## 2ppm sample: 16.3644g
## 8ppm sample: 16.2305g
## 20ppm sample: 16.4321g
## 200ppm sample: 16.2265g


==Notes==
This area is for any observations or conclusions that you would like to note.


==Calculations==


Use categories like tags. Change the "Course" category to the one corresponding to your course. The "Miscellaneous" tag can be used for particular experiments, as instructed by your professor. Please be sure to change or delete this tag as required so that the categories remain well organized.
A 10% clay has 1g of PVA and should have .11g of exfoliated clay.
 
.11g of clay = (4% solution)x = (0.04)x
 
'''x = 2.75g of exfoliated clay solution'''
 
'''Actual mass of solution used was 2.5387g.'''
Figure 1. Shows the calculations for the mass of water in the films.
<br>[[Image:water masses.png]]
 
==DSC Results==
<br>[[Image:PVA.png]]
<br>[[Image:PVA2ppm.png]]
<br>[[Image:PVA8ppm.png]]
<br>[[Image:PVA80ppm.png]]
<br>[[Image:PVA200ppm.png]]
<br>[[Image:pva with clay dsc.png]]
<br>[[Image:2ppm clay dsc.png]]
<br>[[Image:8ppm clay dsc.png]]
<br>[[Image:80ppm clay dsc.png]]
<br>[[Image:200ppm clay dsc.png]]


[[Category:Course]]
[[Category:Course]]

Latest revision as of 00:17, 27 September 2017

Biomaterials Design Lab Main project page
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Objective

Start preparing new films using exfoliated clay. Perform XRD measurement. Continue analysis of DSC and UVVis.

Description

  1. Exfoliated Clays
    1. An exfoliated clay has had all of its layers separated from one another. Instead of having layers in water, you have single sheets of material. This should change the absorption properties of the clay. We are going to test PVA-exfoliated clay materials against the regular PVA-clay material.
    2. To exfoliate clay, you stir it in water for 24 hours. (Luckily Dr. Fox has done this for us already).
    3. Stock solution 4% sodium montmorillonite
      1. Determine how to make a film such that you make a 10% clay (1g of PVA, ?? of exfoliated clay solution).
    4. Prepare a crosslinked film with the exfoliated clay in a similar manner to your other films
  2. Continue DSC analysis
  3. Continue UVVis Analysis
    1. set up new malachite green/PVA-film experiment.
    2. my group set up the 8ppm malachite green (4mL of 200 ppm MG +96mL of water)
    3. two vials with no film were prepared as well to compare the glass absorbance.


Calculations

A 10% clay has 1g of PVA and should have .11g of exfoliated clay.

.11g of clay = (4% solution)x = (0.04)x

x = 2.75g of exfoliated clay solution

Actual mass of solution used was 2.5387g. Figure 1. Shows the calculations for the mass of water in the films.

DSC Results














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