User:Allison K. Alix/Notebook/Thesis Research/2013/10/08
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(→Calculating ω0 using 10000X diluted green fluorescent beads) 
(→Calculating ω0 using 10000X diluted green fluorescent beads) 

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average τ<sub>D</sub> = 36.3137ms = 0.0363137 sec (taken from 10000X beads on 9/4, 9/11, and 9/12)  average τ<sub>D</sub> = 36.3137ms = 0.0363137 sec (taken from 10000X beads on 9/4, 9/11, and 9/12)  
  sqr rt [(0.0363137s)(4)(1.3806488 × 1023 m<sup>2</sup> kg s<sup>2</sup> K<sup>1</sup>)(291.7K)]/[3(0.001028kg/m s)(pi)(2x10<sup>7</sup>) = 5.49x10<sup>7</sup> m =  +  sqr rt [(0.0363137s)(4)(1.3806488 × 1023 m<sup>2</sup> kg s<sup>2</sup> K<sup>1</sup>)(291.7K)]/[3(0.001028kg/m s)(pi)(2x10<sup>7</sup>) = 5.49x10<sup>7</sup> m 
+  
+  '''ω<sub>0</sub> = 0.549um'''  
Revision as of 14:05, 8 October 2013
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Calculationsτ_{D} = (ω_{0}^{2}3ηπd)/4kT where τ_{D} is the diffusion time of the sample ω_{0} is the radius of the spot η is the viscosity of the solvent (water), 0.001028kg/m s d is the diameter of the particle k is Boltzmann's constant = 1.3806488 × 1023 m^{2} kg s^{2}2 K^{1} T is the temperature of the room (18.7 °C, 291.7K) Calculating ω_{0} using 10000X diluted green fluorescent beadsaverage τ_{D} = 36.3137ms = 0.0363137 sec (taken from 10000X beads on 9/4, 9/11, and 9/12) sqr rt [(0.0363137s)(4)(1.3806488 × 1023 m^{2} kg s^{2} K^{1})(291.7K)]/[3(0.001028kg/m s)(pi)(2x10^{7}) = 5.49x10^{7} m ω_{0} = 0.549um
