User:Allison K. Alix/Notebook/Thesis Research/2013/10/08

(Difference between revisions)
 Revision as of 14:02, 8 October 2013 (view source) (→Calculating ω0 using 10000X diluted green fluorescent beads)← Previous diff Revision as of 14:05, 8 October 2013 (view source) (→Calculating ω0 using 10000X diluted green fluorescent beads)Next diff → Line 26: Line 26: average τD = 36.3137ms = 0.0363137 sec (taken from 10000X beads on 9/4, 9/11, and 9/12) average τD = 36.3137ms = 0.0363137 sec (taken from 10000X beads on 9/4, 9/11, and 9/12) - sqr rt [(0.0363137s)(4)(1.3806488 × 10-23 m2 kg s-2 K-1)(291.7K)]/[3(0.001028kg/m s)(pi)(2x10-7) = 5.49x10-7 m = + sqr rt [(0.0363137s)(4)(1.3806488 × 10-23 m2 kg s-2 K-1)(291.7K)]/[3(0.001028kg/m s)(pi)(2x10-7) = 5.49x10-7 m + + '''ω0 = 0.549um'''

Revision as of 14:05, 8 October 2013

Project name Main project page
Previous entry      Next entry

Calculations

τD = (ω023ηπd)/4kT

where τD is the diffusion time of the sample

ω0 is the radius of the spot

η is the viscosity of the solvent (water), 0.001028kg/m s

d is the diameter of the particle

k is Boltzmann's constant = 1.3806488 × 10-23 m2 kg s-2-2 K-1

T is the temperature of the room (18.7 °C, 291.7K)

Calculating ω0 using 10000X diluted green fluorescent beads

average τD = 36.3137ms = 0.0363137 sec (taken from 10000X beads on 9/4, 9/11, and 9/12)

sqr rt [(0.0363137s)(4)(1.3806488 × 10-23 m2 kg s-2 K-1)(291.7K)]/[3(0.001028kg/m s)(pi)(2x10-7) = 5.49x10-7 m

ω0 = 0.549um