User:Allison K. Alix/Notebook/Thesis Research/2013/06/12: Difference between revisions
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SA= 4.657x10<sup>-15</sup>m<sup>2</sup> | SA= 4.657x10<sup>-15</sup>m<sup>2</sup> | ||
SA= 4656.63nm<sup>2</sup> | '''SA= 4656.63nm<sup>2</sup>''' | ||
2) Calculate #PVP per 1 AuNP | 2) Calculate #PVP per 1 AuNP | ||
60PVP/1nm<sup>2</sup> x 4656.63nm<sup>2</sup>/1 AuNP = 279397.5 PVP/1 AuNP | 60PVP/1nm<sup>2</sup> x 4656.63nm<sup>2</sup>/1 AuNP = '''279397.5 PVP/1 AuNP''' | ||
3) Calculate the new concentration of AuNP in nM | 3) Calculate the new concentration of AuNP in nM | ||
M<sub>1</sub>V<sub>1</sub>=M<sub>2</sub>V<sub>2</sub> | |||
(0.43x10<sup>-9</sup>)(13.37mL) = (x)(34.7mL) | |||
x = 1.657x10<sup>-10</sup>M = '''0.1657nM''' | |||
4) Calculate # AuNP in 34.7mL 0.1657nM solution | |||
0.1657x10<sup>-9</sup>mol/L x 34.7mL x 1L/1000mL x 6.02x10<sup>23</sup>AuNP/mol = '''3.46x10<sup>12</sup> AuNP''' | |||
5) Calculate #moles PVP needed to coat AuNP | |||
279397.5 PVP/AuNP x 3.46x10<sup>12</sup>AuNP x 1 mol/6.02x10<sup>23</sup>PVP = 1.6065x10<sup>-6</sup> mol PVP | |||
Revision as of 11:18, 12 June 2013
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AuNP synthesis
Note: These AuNPs will be used in the silica coating procedure. See calculations below. Calculating AuNP diameter and concentration (nM)λspr= 527nm d= [ln(λspr-λ0/L1)]/L2 where λ0= 512nm, L1= 6.53, and L2=0.0216 (These are fit parameters from theoretical calculations1) d= [ln(527nm-512nm/6.53)]/0.0216 d= 38.5nm c = A450/ε450 c = 1.89/(4.36x109) c = 0.43nM Calculating AuNP concentration in g/L1) Calculate the volume of 1 AuNP Volume of 1 AuNP = 4/3πr3, where r = d/2 = 19.25nm V= 4/3π(19.25x10-9m)3 V= 2.988x1023m3 V= 2.988x1017cm3 2) Calculate the mass of 1 AuNP density of Au = 19.3g/cm3 19.3g/cm3 x 2.988x1017cm3 = 5.7668x10-16 g per 1 AuNP 3) Calculate # of AuNP in 20mL solution 0.43x10-9mol/L x 20mL x 1L/1000mL x 6.02x1023AuNP/1 mol = 5.219x1012 AuNP 4) Calculate mass of all AuNP in 20mL solution 5.7668x10-16 g/1 AuNP x 5.219x1012AuNP x 1/20mL x 1000mL/1L = 0.1505g/L Dilution of AuNPAccording to Reference 1, for the silica coating procedure, 34.7mL AuNP with a radius of ~19nM must have a concentration of 0.058g/L M1V1=M2V2 (0.1505g/L)(x)=(0.058g/L)(37.4mL) x = 13.37mL in 21.33mL H2O Calculating the amount of PVP to add to AuNP
1) Calculate the surface area of 1 AuNP Surface Area of a sphere = 4πr2 SA= 4π(19.25x10-9)2 SA= 4.657x10-15m2 SA= 4656.63nm2 2) Calculate #PVP per 1 AuNP 60PVP/1nm2 x 4656.63nm2/1 AuNP = 279397.5 PVP/1 AuNP 3) Calculate the new concentration of AuNP in nM M1V1=M2V2 (0.43x10-9)(13.37mL) = (x)(34.7mL) x = 1.657x10-10M = 0.1657nM 4) Calculate # AuNP in 34.7mL 0.1657nM solution 0.1657x10-9mol/L x 34.7mL x 1L/1000mL x 6.02x1023AuNP/mol = 3.46x1012 AuNP 5) Calculate #moles PVP needed to coat AuNP 279397.5 PVP/AuNP x 3.46x1012AuNP x 1 mol/6.02x1023PVP = 1.6065x10-6 mol PVP
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