User:Allison K. Alix/Notebook/Thesis Research/2013/04/09

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(Procedures)
(Procedures)
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==Procedures==
==Procedures==
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Part 1: Preparation of 2.98μM ethane thiol
+
Part 1: Preparation of 1mL of 2.98μM ethane thiol
 +
 
 +
* original concentrationof AuNP = 19.4nM
 +
* desired concentration of ethanethiol = 19.4nM x(15393) = 298624.2nM = 298μM
 +
* density of ethanethiol = 0.839g/mL
 +
 
 +
1) Calculating concentration of ethanethiol
 +
 
 +
0.839g/mL x 0.025mL = 0.020975g
 +
 
 +
0.020975g/(62.13 g/mol) = 3.376 x 10<sup>-4</sup> mol
 +
 
 +
3.376 x 10<sup>-4</sup> mol/1mL x (1000mL/1L) = 0.34M = 340mM
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 +
340mM (x) = (30mM)(1mL)
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 +
x = 0.088mL = 88μL in 912μL H<sub>2</sub>O
 +
 
 +
30mM (x) = 3mM (1mL)
 +
 
 +
x = 100μL in 900μL
 +
 
 +
3mM(x) = 298μM (1mL)
 +
 
 +
x = 99μL in 901μL to obtain 298μM ethanethiol
 +
 
 +
2) Reacting AuNP with ethanethiol
 +
 
 +
* react 200μL 298μM ethane thiol with 200μL 19.4nM AuNP (synthesized by Dr. Miller)

Revision as of 09:47, 9 April 2013

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Objectives

  • Take Abs and Fluorescence measurements of DNA-MB and DNA-ThT prepared on 4/4/13
  • React ethane-thiol with AuNP

Procedures

Part 1: Preparation of 1mL of 2.98μM ethane thiol

  • original concentrationof AuNP = 19.4nM
  • desired concentration of ethanethiol = 19.4nM x(15393) = 298624.2nM = 298μM
  • density of ethanethiol = 0.839g/mL

1) Calculating concentration of ethanethiol

0.839g/mL x 0.025mL = 0.020975g

0.020975g/(62.13 g/mol) = 3.376 x 10-4 mol

3.376 x 10-4 mol/1mL x (1000mL/1L) = 0.34M = 340mM

340mM (x) = (30mM)(1mL)

x = 0.088mL = 88μL in 912μL H2O

30mM (x) = 3mM (1mL)

x = 100μL in 900μL

3mM(x) = 298μM (1mL)

x = 99μL in 901μL to obtain 298μM ethanethiol

2) Reacting AuNP with ethanethiol

  • react 200μL 298μM ethane thiol with 200μL 19.4nM AuNP (synthesized by Dr. Miller)



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