# User:Allison K. Alix/Notebook/Thesis Research/2013/04/09

(Difference between revisions)
 Revision as of 10:35, 9 April 2013 (view source) (→Procedures)← Previous diff Revision as of 10:47, 9 April 2013 (view source) (→Procedures)Next diff → Line 13: Line 13: ==Procedures== ==Procedures== - Part 1: Preparation of 2.98μM ethane thiol + Part 1: Preparation of 1mL of 2.98μM ethane thiol + + * original concentrationof AuNP = 19.4nM + * desired concentration of ethanethiol = 19.4nM x(15393) = 298624.2nM = 298μM + * density of ethanethiol = 0.839g/mL + + 1) Calculating concentration of ethanethiol + + 0.839g/mL x 0.025mL = 0.020975g + + 0.020975g/(62.13 g/mol) = 3.376 x 10-4 mol + + 3.376 x 10-4 mol/1mL x (1000mL/1L) = 0.34M = 340mM + + 340mM (x) = (30mM)(1mL) + + x = 0.088mL = 88μL in 912μL H2O + + 30mM (x) = 3mM (1mL) + + x = 100μL in 900μL + + 3mM(x) = 298μM (1mL) + + x = 99μL in 901μL to obtain 298μM ethanethiol + + 2) Reacting AuNP with ethanethiol + + * react 200μL 298μM ethane thiol with 200μL 19.4nM AuNP (synthesized by Dr. Miller)

## Revision as of 10:47, 9 April 2013

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## Objectives

• Take Abs and Fluorescence measurements of DNA-MB and DNA-ThT prepared on 4/4/13
• React ethane-thiol with AuNP

## Procedures

Part 1: Preparation of 1mL of 2.98μM ethane thiol

• original concentrationof AuNP = 19.4nM
• desired concentration of ethanethiol = 19.4nM x(15393) = 298624.2nM = 298μM
• density of ethanethiol = 0.839g/mL

1) Calculating concentration of ethanethiol

0.839g/mL x 0.025mL = 0.020975g

0.020975g/(62.13 g/mol) = 3.376 x 10-4 mol

3.376 x 10-4 mol/1mL x (1000mL/1L) = 0.34M = 340mM

340mM (x) = (30mM)(1mL)

x = 0.088mL = 88μL in 912μL H2O

30mM (x) = 3mM (1mL)

x = 100μL in 900μL

3mM(x) = 298μM (1mL)

x = 99μL in 901μL to obtain 298μM ethanethiol

2) Reacting AuNP with ethanethiol

• react 200μL 298μM ethane thiol with 200μL 19.4nM AuNP (synthesized by Dr. Miller)