User:Allison K. Alix/Notebook/CHEM-581/2012/10/26

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<math>\frac {278.01 g} {mol} \times \frac {50 x 10^-3 mol} {L} \times \frac {1 L} {1000 mL} \times 10mL = 0.138 g</math>
<math>\frac {278.01 g} {mol} \times \frac {50 x 10^-3 mol} {L} \times \frac {1 L} {1000 mL} \times 10mL = 0.138 g</math>
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0.138 g Fe<sub>2</sub>(SO<sub>4</sub> in 10mL H<sub>2</sub>O to get 50mM. Dilute to 50μM by using 0.01 mL (10μL) in 9.99mL (9990μL) H<sub>2</sub>O
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0.138 g Fe<sub>2</sub>(SO<sub>4</sub>)<sub>3</sub> in 10mL H<sub>2</sub>O to get 50mM. Dilute to 50μM by using 0.01 mL (10μL) in 9.99mL (9990μL) H<sub>2</sub>O
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[[Image:GraphImage.png‎]]
[[Image:GraphImage.png‎]]

Current revision

Experimental Chemistry Main project page
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Objective

  • Take UV-Vis spectra of mixtures of previously prepared salt solutions and porphyrin solution in 1:1 ratio at the same concentrations (50micM)
  • Take IR spectra of films

Description

  1. Finish preparing the following sulfate solutions
    1. 10mL 50 μM H2SO4
    2. 10mL 50 μM Fe2(SO4)3
  2. Begin taking IR measurements of all films synthesized thus far

Data

Preparation of 50μM H2SO4

\frac {50 x 10^-3 mol} {L} \times \frac {98.07 g} {mol} \times 10mL \times \frac {1L} {1000 mL} \times \frac {1mL} {1.84 g} = 0.0266mL

0.0266mL = 26.65μL

Preparation of 50μM Fe2(SO4)3

\frac {278.01 g} {mol} \times \frac {50 x 10^-3 mol} {L} \times \frac {1 L} {1000 mL} \times 10mL = 0.138 g

0.138 g Fe2(SO4)3 in 10mL H2O to get 50mM. Dilute to 50μM by using 0.01 mL (10μL) in 9.99mL (9990μL) H2O

Image:GraphImage.png‎

Notes

This area is for any observations or conclusions that you would like to note.


Use categories like tags. Change the "Course" category to the one corresponding to your course. The "Miscellaneous" tag can be used for particular experiments, as instructed by your professor. Please be sure to change or delete this tag as required so that the categories remain well organized.



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