User:Allison K. Alix/Notebook/CHEM-581/2012/10/26
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<div class="center" style="width:auto; margin-left:auto; margin-right:auto;">Preparation of 50μM H<sub>2</sub>SO<sub>4</sub></div> | <div class="center" style="width:auto; margin-left:auto; margin-right:auto;">Preparation of 50μM H<sub>2</sub>SO<sub>4</sub></div> | ||
| - | <math>\frac {50 x 10^-3 mol} {L} \times \frac {98.07 g} {mol} \times 10mL \times \frac {1L} {1000 mL} \times \frac {1mL} {1.84 g} = 0.0266mL = 26. | + | <math>\frac {50 x 10^-3 mol} {L} \times \frac {98.07 g} {mol} \times 10mL \times \frac {1L} {1000 mL} \times \frac {1mL} {1.84 g} = 0.0266mL</math> |
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| + | 0.0266mL = 26.65μL | ||
| + | ---- | ||
| + | <div class="center" style="width:auto; margin-left:auto; margin-right:auto;">Preparation of 50μM Fe<sub>2</sub>(SO<sub>4</sub>)<sub>3</sub></div> | ||
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| + | <math>\frac {278.01 g} {mol} \times \frac {50 x 10^-3 mol} {L} \times \frac {1 L} {1000 mL} \times 10mL = 0.138 g in 10mL </math> | ||
[[Image:GraphImage.png]] | [[Image:GraphImage.png]] | ||
Revision as of 16:24, 6 November 2012
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Objective
Description
DataPreparation of 50μM H2SO4
0.0266mL = 26.65μL Preparation of 50μM Fe2(SO4)3
NotesThis area is for any observations or conclusions that you would like to note.
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