User:Allison K. Alix/Notebook/CHEM-581/2012/10/26
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<div class="center" style="width:auto; margin-left:auto; margin-right:auto;">Preparation of 50μM H<sub>2</sub>SO<sub>4</sub></div> | <div class="center" style="width:auto; margin-left:auto; margin-right:auto;">Preparation of 50μM H<sub>2</sub>SO<sub>4</sub></div> | ||
| - | <math>\frac {50 x 10^-3 mol} {L} \times \frac {98.07 g} {mol} \times 10mL \times \frac {1L} {1000 mL} \times \frac {1mL} {1.84 g} = 0.0266mL | + | <math>\frac {50 x 10^-3 mol} {L} \times \frac {98.07 g} {mol} \times 10mL \times \frac {1L} {1000 mL} \times \frac {1mL} {1.84 g} = 0.0266mL</math> |
| + | 0.0266mL = 26.65μL | ||
| + | ---- | ||
| + | <div class="center" style="width:auto; margin-left:auto; margin-right:auto;">Preparation of 50μM Fe<sub>2</sub>(SO<sub>4</sub>)<sub>3</sub></div> | ||
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| + | <math>\frac {278.01 g} {mol} \times \frac {50 x 10^-3 mol} {L} \times \frac {1 L} {1000 mL} \times 10mL = 0.138 g</math> | ||
| + | |||
| + | 0.138 g Fe<sub>2</sub>(SO<sub>4</sub>)<sub>3</sub> in 10mL H<sub>2</sub>O to get 50mM. Dilute to 50μM by using 0.01 mL (10μL) in 9.99mL (9990μL) H<sub>2</sub>O | ||
| + | ---- | ||
[[Image:GraphImage.png]] | [[Image:GraphImage.png]] | ||
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Objective
Description
DataPreparation of 50μM H2SO4
0.0266mL = 26.65μL Preparation of 50μM Fe2(SO4)3
0.138 g Fe2(SO4)3 in 10mL H2O to get 50mM. Dilute to 50μM by using 0.01 mL (10μL) in 9.99mL (9990μL) H2O NotesThis area is for any observations or conclusions that you would like to note.
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