User:Alicia Rasines Mazo/Notebook/CHEM-581 Experimental Chemistry I/2014/09/24: Difference between revisions
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*239.4 μM: | *239.4 μM: | ||
**PVA-Clay film | |||
{| {{table}} | |||
|- | |||
! PVA-Clay in | |||
! R6G dye left in solution (μM) | |||
! R6G dye absorbed by film (μM) | |||
|- | |||
| 239.4 μM R6G | |||
| 38.79 | |||
| 200.6 | |||
|- | |||
| 119.7 μM R6G | |||
| 15.09 | |||
| 104.6 | |||
|- | |||
| 11.97 μM R6G | |||
| 0.776 | |||
| 11.19 | |||
|- | |||
|} | |||
10 mL of R6G solution were added to each vial, so that if 11.194 μM were absorbed from the 11.97 μM solution, moles absorbed=(11.194×10<sup>-6</sup>moles)/0.010L=0.0011194 moles. | |||
*mass of R6G dye absorbed=0.0011194 moles × 479.02g/mol=0.5362 g | |||
*11.97 μM: (0.5362 g R6G/0.1179 film)=''' 4.55 g R6G/g film''' | |||
*119.7 μM: ''' g R6G/g film''' | |||
*239.4 μM: | |||
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Revision as of 11:13, 17 October 2014
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Tasks for September 24
Preparation of 10% wt new exfoliated clay films
Completing synthesis of films
Run AA on As samples
To be done at a later date since As lamp was burnt out Measuring fluorescence of Rhodamine dye by filmsNote: the initial concentration of rhodamine was incorrectly labeled as 159μM, actual concentration was 1.9 mM<br.> Solutions were made for 20, 10 and 1 μM R6G by:
10mL of each R6G dye solution were added to the PVA and PVA-Clay glass vials and the glass vials were placed inside a dark drawer to allow the films to soak the fluorescent dye.
10mL of each R6G dye solution were added to the PVA and PVA-Clay glass vials and the glass vials were placed inside a dark drawer to allow the films to soak the fluorescent dye.
10mL of each R6G dye solution were added to the PVA and PVA-Clay glass vials and the glass vials were placed inside a dark drawer to allow the films to soak the fluorescent dye.
Measuring absorbance of R6G dye by polymer and clay films
10 mL of R6G solution were added to each vial, so that if 10.894 μM were absorbed from the 11.97 μM solution, moles absorbed=(10.894×10-6moles)/0.010L=0.0010894 moles.
10 mL of R6G solution were added to each vial, so that if 11.194 μM were absorbed from the 11.97 μM solution, moles absorbed=(11.194×10-6moles)/0.010L=0.0011194 moles.
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