IGEM:MIT/2005/Sandbox

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Revision as of 08:28, 4 May 2005 by >Jenny
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[math]\displaystyle{ x = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a} }[/math]


[math]\displaystyle{ \int_0^\sqrt\pi\int_0^x \sin x^2\,dy\,dx }[/math]