Cell cycle analysis: Difference between revisions

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This gives:
This gives:


'''<math>a_i=\tau-\frac{log(2-F)}{log2}*\tau</math>'''    
'''<math>a_i=\tau-\frac{log(2-F)}{log2}*\tau</math>'''  
 
which is the same as this (log2 is 1):
 
'''<math>a_i=\tau-log(2-F)*\tau</math>'''


If you have for example a generation time τ=84 minutes and the portion of cells with 4 origins is 66% the formula gives:                                                             
If you have for example a generation time τ=84 minutes and the portion of cells with 4 origins is 66% the formula gives:                                                             




'''<math>a_i=84-\frac{log(2-0.66)}{log2}*84=48.5</math>'''  
'''<math>a_i=84-log(2-0.66)*84=48.5</math>'''  




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[[Image:C+D_1.jpg|left|250px]]
[[Image:C+D_1.jpg|left|250px]]


===Determination of the C and D periods:===
===Determination of the C and D periods:===
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'''<math>C=log(\frac{oriC}{terC})*{\tau}</math>'''
'''<math>C=log2(\frac{oriC}{terC})*{\tau}</math>'''





Revision as of 04:24, 1 July 2013

Cell cycle analysis of Escherichia coli cells

C period = the time for a round of chromosome replication

D period = the time between the end of a round of chromosome replication and cell division


Determination of initiation age (ai) and C+D:

From flow cytometry analysis of cells treated with rifampicin and cephalexin (run-out histogram) the proportions of cells that had not initiated replication at the time of drug action (4-origin-cells, streaked) and cells that had initiated (8-origin-cells) can be estimated.The initiation age (ai) can be found from the theoretical age distribution described by this formula,

[math]\displaystyle{ F=2-2^{\frac{(\tau-a_i)}{\tau}} }[/math]


where F is the fraction of cells that had not initiated and τ is the generation time, or from the estimated graph of the theoretical age distribution (streaked portion).

This gives:

[math]\displaystyle{ a_i=\tau-\frac{log(2-F)}{log2}*\tau }[/math]

which is the same as this (log2 is 1):

[math]\displaystyle{ a_i=\tau-log(2-F)*\tau }[/math]

If you have for example a generation time τ=84 minutes and the portion of cells with 4 origins is 66% the formula gives:


[math]\displaystyle{ a_i=84-log(2-0.66)*84=48.5 }[/math]


The C+D period is estimated from the initiation age (ai), the generation time (τ) and the number of generations spanned per cell cycle.


Example:

4-origin-cells: 23 %

Generation time (τ): 27 min

Initiation age (ai): 5 min


Determination of the C and D periods:

The C period is found from the oriC/terC ratio obtained by Southern blot or qPCR analysis (oriC/ter ratio determination) and the generation time (τ):

[math]\displaystyle{ \frac{oriC}{terC}=2^{\frac{C}{\tau}} }[/math]


which gives:


[math]\displaystyle{ C=log2(\frac{oriC}{terC})*{\tau} }[/math]


The D period is found from the C+D and C period:

[math]\displaystyle{ D = (C+D) - C }[/math]


Example (continues):

C period calculated from the oriC/terC ratio: 49 min

D period = (C+D) – C

D period = 76 min – 49 min = 27 min


The theoretical exponential DNA histogram:

A theoretical exponential DNA histogram can be drawn to check whether the obtained values fit with the experimental data. From the C+D period the DNA content of the cells at different time points in the cell cycle can be calculated.

Example:

















The individual values of C and D can be varied

to obtain a shape of the theoretical histogram

that gives the best fit to the experimental histogram.








Calculation of the average number of replication forks when D=τ:

In the example given above, 23% of the cells contain 4 replication forks (4-origin peak in run-out histogram) and 77% contain 12 replication forks (8-origin peak), hence the average number of replication forks in the cell population will be:

(4 x 0.23) + (12 x 0.77) = 10.2 forks



Calculation of the average number of replication forks when D≠τ:

Example:

4-origin-cells: 23%

8-origin-cells: 77%

τ = 27 min

ai = 5 min

C = 51 min

D = 25 min

C+D = 76 min















12 forks → 8-origin peak in run-out histogram = 77% of the cells

6 and 4 forks → 4-origin peak in run-out histogram = 23% of the cells

The fraction of cells containing 6 forks: F = 2 - 2((τ-at)/τ) = 2 – 2((27-2)/27) = 0.10

The fraction of cells containing 4 forks: 0.23 – 0.10 = 0.13

The average number of replication forks: (6 x 0.10) + (4 x 0.13) + (12 x 0.77) = 10.4 forks