Cell cycle analysis
From OpenWetWare
(→Determination of the C and D periods:) |
Current revision (14:20, 4 May 2011) (view source) (→Determination of initiation age (ai) and C+D:) |
||
| (One intermediate revision not shown.) | |||
| Line 17: | Line 17: | ||
This gives: | This gives: | ||
| - | '''<math>a_i=\tau-\frac{log(2-F)}{log2}*\tau</math>''' | + | '''<math>a_i=\tau-\frac{log(2-F)}{log2}*\tau</math>''' |
| + | |||
| + | which is the same as this (log2 is 1): | ||
| + | |||
| + | '''<math>a_i=\tau-log(2-F)*\tau</math>''' | ||
If you have for example a generation time τ=84 minutes and the portion of cells with 4 origins is 66% the formula gives: | If you have for example a generation time τ=84 minutes and the portion of cells with 4 origins is 66% the formula gives: | ||
| - | '''<math>a_i=84- | + | '''<math>a_i=84-log(2-0.66)*84=48.5</math>''' |
| Line 40: | Line 44: | ||
[[Image:C+D_1.jpg|left|250px]] | [[Image:C+D_1.jpg|left|250px]] | ||
| - | |||
| - | |||
| - | |||
| - | |||
| - | |||
| - | |||
| - | |||
| - | |||
| - | |||
| - | |||
===Determination of the C and D periods:=== | ===Determination of the C and D periods:=== | ||
| Line 56: | Line 50: | ||
'''<math>\frac{oriC}{terC}=2^{\frac{C}{\tau}}</math>''' | '''<math>\frac{oriC}{terC}=2^{\frac{C}{\tau}}</math>''' | ||
| + | |||
which gives: | which gives: | ||
| - | '''<math>\frac{oriC}{terC} | + | |
| + | '''<math>C=log(\frac{oriC}{terC})*{\tau}</math>''' | ||
Current revision
Cell cycle analysis of Escherichia coli cells
C period = the time for a round of chromosome replication
D period = the time between the end of a round of chromosome replication and cell division
Contents |
Determination of initiation age (ai) and C+D:
From flow cytometry analysis of cells treated with rifampicin and cephalexin (run-out histogram) the proportions of cells that had not initiated replication at the time of drug action (4-origin-cells, streaked) and cells that had initiated (8-origin-cells) can be estimated.The initiation age (ai) can be found from the theoretical age distribution described by this formula,
where F is the fraction of cells that had not initiated and τ is the generation time, or from the estimated graph of the theoretical age distribution (streaked portion).
This gives:
which is the same as this (log2 is 1):
ai = τ − log(2 − F) * τ
If you have for example a generation time τ=84 minutes and the portion of cells with 4 origins is 66% the formula gives:
ai = 84 − log(2 − 0.66) * 84 = 48.5
The C+D period is estimated from the initiation age (ai), the generation time (τ) and the number of generations spanned per cell cycle.
Example:
4-origin-cells: 23 %
Generation time (τ): 27 min
Initiation age (ai): 5 min
Determination of the C and D periods:
The C period is found from the oriC/terC ratio obtained by Southern blot or qPCR analysis (oriC/ter ratio determination) and the generation time (τ):
which gives:
The D period is found from the C+D and C period:
D = (C + D) − C
Example (continues):
C period calculated from the oriC/terC ratio: 49 min
D period = (C+D) – C
D period = 76 min – 49 min = 27 min
The theoretical exponential DNA histogram:
A theoretical exponential DNA histogram can be drawn to check whether the obtained values fit with the experimental data. From the C+D period the DNA content of the cells at different time points in the cell cycle can be calculated.
Example:
The individual values of C and D can be varied
to obtain a shape of the theoretical histogram
that gives the best fit to the experimental histogram.
Calculation of the average number of replication forks when D=τ:
In the example given above, 23% of the cells contain 4 replication forks (4-origin peak in run-out histogram) and 77% contain 12 replication forks (8-origin peak), hence the average number of replication forks in the cell population will be:
(4 x 0.23) + (12 x 0.77) = 10.2 forks
Calculation of the average number of replication forks when D≠τ:
Example:
4-origin-cells: 23%
8-origin-cells: 77%
τ = 27 min
ai = 5 min
C = 51 min
D = 25 min
C+D = 76 min
12 forks → 8-origin peak in run-out histogram = 77% of the cells
6 and 4 forks → 4-origin peak in run-out histogram = 23% of the cells
The fraction of cells containing 6 forks: F = 2 - 2((τ-at)/τ) = 2 – 2((27-2)/27) = 0.10
The fraction of cells containing 4 forks: 0.23 – 0.10 = 0.13
The average number of replication forks: (6 x 0.10) + (4 x 0.13) + (12 x 0.77) = 10.4 forks


