Biomod/2011/TUM/TNT/LabbookA/Calculation of intercalator concentrations: Difference between revisions

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<div id="struktur">
=Calculation of DNA binder concentrations=
=Calculation of DNA binder concentrations=
==Intention==
==Intention==
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<math>K_{D} = \frac{c_{B}c_{bp}}{c_{B bp}}</math>
<math>K_{D} = \frac{c_{B}c_{bp}}{c_{B bp}}</math>


with <math>K_{D}</math> the dissociation constant of the DNA binder, <math>c_{B}</math> the concentration of DNA binder, <math>c_{bp}</math> the concentration of base pairs and <math>c_{B bp}</math> the concentration of the occupied basepairs
with <math>K_{D}</math> the dissociation constant of the DNA binder, <math>c_{B}</math> the concentration of DNA binder, <math>c_{bp}</math> the concentration of base pairs and <math>c_{B bp}</math> the concentration of the occupied basepairs<br>
<br>
However, this formula is not suited for such small concentrations, therefore we derived a more exact one.


==Derivation==
==Derivation==
* Take the dissociation constant K<sub>D</sub> and replace the concentrations with the total concentrations of the DNA binders and base pairs:
* Take the dissociation constant K<sub>D</sub> and replace the concentrations with the total concentrations of the DNA binders and base pairs:


<math>{c_{B}}^{T} = c_{B bp} + c_{B}</math> → <math>c_{B}= c_{B bp} - {c_{B}}^{T} </math>
<math>{c_{B}}^{T} = c_{B bp} + c_{B}</math> → <math>c_{B}= {c_{B}}^{T} - c_{B bp} </math>


and
and


<math>{c_{bp}}^{T} = c_{B bp} + c_{bp}</math> → <math>c_{bp} = c_{B bp} - {c_{bp}}^{T}</math>
<math>{c_{bp}}^{T} = c_{B bp} + c_{bp}</math> → <math>c_{bp} = {c_{bp}}^{T} - c_{B bp} </math>


* Now assume that every n-th base a DNA binder should have bound in equilibrium
* Now assume that every n-th base a DNA binder should have bound in equilibrium


<math>{c_{B bp}} = \frac{c_{bp}}{n}</math>
<math>{c_{B bp}} = \frac{{c_{bp}}^T}{n}</math>


* With this, we get to a K<sub>D</sub> which is only dependent on the total concentrations of base pairs (c.f. structure) and DNA binders
* With this, we get to a K<sub>D</sub> which is only dependent on the total concentrations of base pairs (c.f. structure) and DNA binders
Line 30: Line 32:


<math>{c_{B}}^{T} = \frac{K_{D}}{n -1} + \frac{{c_{bp}}^{T}}{n}</math>
<math>{c_{B}}^{T} = \frac{K_{D}}{n -1} + \frac{{c_{bp}}^{T}}{n}</math>
</div>

Latest revision as of 19:24, 2 November 2011

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Calculation of DNA binder concentrations

Intention

  • First approach was to determine the appropriate concentrations of DNA binders with a simple approximation:

[math]\displaystyle{ K_{D} = \frac{c_{B}c_{bp}}{c_{B bp}} }[/math]

with [math]\displaystyle{ K_{D} }[/math] the dissociation constant of the DNA binder, [math]\displaystyle{ c_{B} }[/math] the concentration of DNA binder, [math]\displaystyle{ c_{bp} }[/math] the concentration of base pairs and [math]\displaystyle{ c_{B bp} }[/math] the concentration of the occupied basepairs

However, this formula is not suited for such small concentrations, therefore we derived a more exact one.

Derivation

  • Take the dissociation constant KD and replace the concentrations with the total concentrations of the DNA binders and base pairs:

[math]\displaystyle{ {c_{B}}^{T} = c_{B bp} + c_{B} }[/math][math]\displaystyle{ c_{B}= {c_{B}}^{T} - c_{B bp} }[/math]

and

[math]\displaystyle{ {c_{bp}}^{T} = c_{B bp} + c_{bp} }[/math][math]\displaystyle{ c_{bp} = {c_{bp}}^{T} - c_{B bp} }[/math]

  • Now assume that every n-th base a DNA binder should have bound in equilibrium

[math]\displaystyle{ {c_{B bp}} = \frac{{c_{bp}}^T}{n} }[/math]

  • With this, we get to a KD which is only dependent on the total concentrations of base pairs (c.f. structure) and DNA binders

[math]\displaystyle{ K_{D} = ({c_{B}}^{T} - \frac{{c_{bp}}^{T}}{n}) (n -1) }[/math]

Result

  • Now we are able to calculate the right concentration of the DNA binders in the sample to get an occupancy of n (i.e. one DNA binder each n-th base pair)

[math]\displaystyle{ {c_{B}}^{T} = \frac{K_{D}}{n -1} + \frac{{c_{bp}}^{T}}{n} }[/math]