BME100 s2015:Group2 12pmL2: Difference between revisions

From OpenWetWare
Jump to navigationJump to search
Line 32: Line 32:


'''Experiment 2'''<br>
'''Experiment 2'''<br>
 
[[Image:Data Rats.png‎|500px|Descriptive Stats of Rat data]]
<a href="http://imgur.com/qXhNbZt"><img src="http://i.imgur.com/qXhNbZt.png" title="source: imgur.com" /></a>


<br><br>
<br><br>

Revision as of 14:36, 28 January 2015

BME 100 Spring 2015 Home
People
Lab Write-Up 1 | Lab Write-Up 2 | Lab Write-Up 3
Lab Write-Up 4 | Lab Write-Up 5 | Lab Write-Up 6
Course Logistics For Instructors
Photos
Wiki Editing Help

OUR TEAM

Name: Levi Riley
Name: Alexandria Clark
Name: Blossom Mendonca
Name: Alina Kilic
Name: Trevor Douglass
Name: Andre Dang


LAB 2 WRITE-UP

Descriptive Statistics

Experiment 1
Descriptive Stats of Human data


Experiment 2
Descriptive Stats of Rat data



Results

Experiment 1
<a href="http://imgur.com/YxJGx6O"><img src="http://i.imgur.com/YxJGx6O.png"


Experiment 2

<a href="http://imgur.com/gtw8ijv"><img src="http://i.imgur.com/gtw8ijv.png"


A T-Test was used to determine whether or not there is a statistically significant difference in the inflammotin found in the body of rats due to the change in dosage of LPS from 0mg to 10mg. The results of the t-test were approximately 0.87, which shows there is no correlation between the change in dosage- this is because the maximum number for it to be statistically significant is 0.05.




Analysis

Experiment 1
For the study with Humans, the ANOVA test was used because there were more than 2 data sets to be compared. Then, the Bonferoni Correction test was used by implementing the t-test to find the corrective p-value for each of the 6 comparisons (example: 0mg vs. 5mg and 0mg vs. 10mg). These p-values were used to determine the significance between the the p-value of 0.0083 (0.05 divided by 6) with the t-test value for each of the 6 comparisons. The values were deemed significant because of the great differences.


Experiment 2
During the rat study, the dosage amount of 0mg changed the amounts of inflammotin within the rats was equal to the amount of inflammoton with the 10mg dosage, both averaging out to 10.516 for 0mg and 11.112 for 10mg which shows the deviation to be insignificant and making it statistically insignificant. Result from the standard deviation shows that the level of inflammotin within the test subjects with 0mg and 10mg dosage varied.



Summary/Discussion

For the Rat test the T-Test was used to analyse the data, the T-test was chosen because the rats experiment only included two data sets-so ANOVA was not necessary. In the Rat test, there was no significant statistical difference, and so there was no importance in the difference between 0mg and 10mg in rats. However, in the human study where 0, 5, 10, 15 mg were used there was a significant difference between each of the 4 doses. In the human inflammotin test, there were six comparisons used to test for variance. The human inflammotin test needed to use the ANOVA because there were 3 data sets that were tested.