IGEM:IMPERIAL/2007/Projects/Biofilm Detector/Modelling/Construct1

=Construct 1: Introduction=

 Introduction Case 1 References  

With the chemical pathway below for construct 1 we can make form some initial equations about the system.



Our aim in modelling Infector Detector is to determine the concentration of biofilm we can detect such that we report a visible signal. Therefore we want to relate the GFP concentration to the concentration of AHL. Starting that the rate of change in GFP concentration:


 * $$\frac{d[GFP]}{dt}=k_{6}[AP]-\delta_{GFP}[GFP]\cdots\cdots(1)$$

Aussume : [AP] reaches a constant level Reason : Treat 1st formation of AP complex as a black box - it just reaches steady state.


 * $$\therefore\frac{d[AP]}{dt}=0=k_{4}[A][P]-k_{5}[AP]\cdots\cdots(2)$$


 * $$\Rightarrow[AP]=\frac{k_{4}}{k_{5}}[A][P]\cdots\cdots(3)$$

Assume : Conservation of Plux Promoters Reason : no damage to Promoters will occour eg. no DNA damage due to old age or cell defence mechanisms attacking the DNA


 * $$\displaystyle[P]_{0}=[P]+[AP]\cdots\cdots(4)$$


 * $$\displaystyle[P]=[P]_{0}-[AP]\cdots\cdots(5)$$

Substitute this into (3)


 * $$[AP]=\frac{k_{4}}{k_{5}}[A]\left([P]_{0}-[AP]\right)\cdots\cdots(6)$$

Solving for [AP]


 * $$[AP]+\frac{k_{4}}{k_{5}}[A][AP]=\frac{k_{4}}{k_{5}}[A][P]_{0}\cdots\cdots(7)$$


 * $$[AP]\left(1+\frac{k_{4}}{k_{5}}[A]\right)=\frac{k_{4}}{k_{5}}[A][P]_{0}\cdots\cdots(8)$$


 * $$[AP]=\frac{k_4[A][P]_{0}}{k_{5}+k_{4}[A]}=\frac{K_{\beta}[A][P]_{0}}{1+K_{\beta}[A]}\cdots\cdots(9)$$


 * $$K_{\beta}=\frac{k_{4}}{k_{5}}$$

From 9 $$\because$$ [AP] is a constant [A] is a constant

From Reaction pathways at top of page we can see that because 3 is in equilibrium 2 is in equilibrium

From these two statements we can say that at equilibrium:


 * $$[A]=K_{\alpha}[AHL][LuxR]\cdots\cdots(10)$$


 * $$K_{\alpha}=\frac{k_{2}}{k_{3}}$$

Substituting all of this into expression for GFP


 * $$\frac{d[GFP]}{dt}=k_{6}\left[\frac{K_{\alpha}K_{\beta}[AHL][LuxR][P]_{0}}{1+K_{\alpha}K_{\beta}[AHL][LuxR]}\right]-\delta_{GFP}[GFP]\cdots\cdots(11)$$