IGEM:UNAM/2009/Notebook/Modeling logbook Claudia/2010/04/06

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Objective: Calculate the photon flux that saturates the LovTAP receptor.
In Strickland et al. is reported that LovTAP is saturated with 20 mW/cm^2 irradiance at 470 nm.


 * Conversion to photons:

Using the following formula:

The energy E of a photon is   E = hc / λ

where h is Planck's Constant, h = 6.626176 x 10^-34 J•s

The velocity of any photon is c, the speed of light=3 * 10^8 m/ s

And λ the wavelength of the photon that in this case is 470 x 10^-9 m (470 nm).

Thus,

E= ((6.63 * (10^(-34))) * (3 * (10^8))) / (470 * (10^(-9))) E= 4.23191489 × 10^-19 J

The photon flux density (Φ ) at a given light intensity is: Φ= P/ E

where P is the light intensity in Watts and E the energy of a photon in Jules.

Substituting:

P= 0.02 Watts and E= 4.23191489 × 10^-19 J. Φ= 0.02/ (4.23191489 * 10^-19 ) = 4.72599297 × 10^16 photons/s•cm2