Physics307L F09:People/Gooden/Notebook/071001

SPEED OF LIGHT EXPERIMENT

Overview

 * This experiment is to measure the speed of light, which is one of physics most important constants. The experiment uses a photomultiplier tube and a green LED. The LED sends pulses of light down a darkened tube where the light pulses are picked up by the PMT(photomultiplier tube). Both the PMT and LED send signals to the Time-Amplitude Converter(TAC)which using an oscilloscope shows us the output wave of the TAC and then due to it being vary chaotic you must attempt to average over the amplitudes to determine an approximate time-delay.

Procedure

 * This experiment requires using a lot of different equipment

Time-Amplitude Converter (TAC)

LED

DC Power supply (150V-200V)

DC Power supply (1800V-2000V)

Photomultiplier Tube (PMT)

Oscilloscope

Delay box


 * To start you must connect the power supplies to both the LED and the PMT that are at either ends of the tube, the low and high voltage supplies respectively. Then connect the LED to the TAC's start jack with a BNC cable, and also connect the PMT to the stop jack on the TAC with another BNC cable. Next you also want to run a cable from the PMT (PMT power supply)to the oscilloscope to Channel 1 and from the TAC to channel 2 on the oscilloscope. The oscilloscope will measure the voltage output from the PMT on channel 1 and the signal from the TAC will respresent the time delay that you want to be measuring.
 * Once all set up, you want to pick a value of the voltage on Ch 1 and attempt to maintain that value for your measurments. This is accomplished by turning the PMT left/right to allign or unallign its polarizer with that of the LED.
 * Next, using the aquire button on the oscilloscope you can choose to average over the values that the oscilloscope is recieving to allow you to take measurments. You want to choose the 128 setting under the average command, so the signal is more stable. Then use the measure function to allow you to see the values outputed to channels 1 and 2 to make your measurments.
 * Then start making measurments! - to do this you must pick your desired value for channel 1 and then holding the PMT steady have your partner pull or push the meter stick connected to the LED in or out of the tube. Record how far the meter stick moved relative to the opening of the tube and then readjust the PMT so that channel 1 on the oscilloscope returns to your previously picked value.Then simply continue.

Data
Set 1 V=3.24 +/-.04 d=60 V=3.2 +/-.04 d=80 V=3.08 +/-.04 d=100 V=3.00 +/-.04 d=120 V=2.96 +/-.04 d=140 V=3.00 +/-.04 d=130 V=3.12 +/-.04 d=90 V=3.2 +/-.04 d=70
 * Below is the data collected. Our picked value of the PMT voltage (Ch 1) is given for each set along with a +/- range that the oscilloscope tended to oscillate its values by around our value.Then next to each measured value of the TAC voltage is the distance the LED was moved in cm.
 * Ch1 600 +/- 8 mV

Set 2 V=2.44 d=70 V=2.40 d=80 V=2.36 d=90 V=2.32 d=100 V=2.32 d=110
 * Ch1 800+/- 8 mV

Set 3 V=2.80 d=27.5 V=2.64 d=70 V=2.52 d=110 V=2.44 d=130 V=2.72 d=50
 * Ch1 720 */- 8 mV

Calculations

 * Given the measured voltage from Ch2 we are able to calculate a time that the voltage corresponds to using:


 * $$V = G*T$$

given that G is the gain and from how we set up the TAC was 10/100 Volts/sec or G=.1 V/s, which was explained and given to us by Dr. Koch.


 * solving the equation for T and then using our voltage values above we find our corresponding times to be:Time in nanoseconds

Set 1 - times t=32.4 t=32 t=30.8 t=30 t=29.6 t=30 t=31.2 t=32

Set 2 - times t=24.4 t=24 t=23.6 t=23.2 t=23.2

Set 3 - times t=28 t=26.4 t=25.2 t=24.4 t=27.2

Analysis
$$c=\left(2.68 \pm 0.18\right)\times10^{8} m/s$$
 * Taking the distances measured at the particular voltages and the times given above we plotted and computed a least-squares fit to each data set. However the distances measured give usso at Dr. koch's advice to correct it we subtracted each distance in meters from 2m before plotting.
 * Data Set 1

$$c=\left(2.94 \pm 0.42\right)\times10^{8} m/s$$
 * Data Set 2

$$c=\left(2.89 \pm 0.08\right)\times10^{8} m/s$$
 * Data Set 3

Results

 * By averaging our three values of the speed of light we find that from this experiment the speed of light is:

$$c=\left(2.83 \pm .23\right)\times10^8 m/s$$

Discussion

 * The result given above is in excellent agreement with the accepted value of the speed of light which is $$c=2.99\times 10^8 m/s$$ so we are very happy about the results.